Answer
0
Work Step by Step
$\lim\limits_{x \to -\infty}\frac{x}{\sqrt {x^2+1}}= \lim\limits_{x \to -\infty}\frac{x}{x\sqrt {1+1/x^2}}=\lim\limits_{x \to -\infty}\frac{1}{\sqrt {1+1/x^2}} = 1/\sqrt \infty = 0$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 3 - Applications of Differentiation - 3.5 Exercises - Page 202: 28
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
