Answer
$x^2-4x+5=0$
Work Step by Step
As we are given that the roots of a quadratic equation as :
{$x-2-i,x-2+i$}
Let us find a quadratic equation for the given roots:
$(x-2-i)(x-2+i)=0$
This implies that after simplifications, we have
$(x-2-i)(x-2+i)=0$
or, $(x-2)^2-i^2=0$
or, $x^2-4x+4-(-1)=0$ [ since, $i^2=-1$]
Thus, $x^2-4x+5=0$
