Answer
$x^2-3=0$
Work Step by Step
As we are given that solution set : {$-\sqrt 3,\sqrt 3$}
This implies that $x=-\sqrt 3,\sqrt 3$
As per zero-product reverse property, we have $(x+\sqrt 3)(x-\sqrt 3)=0$
Now, apply FOIL METHOD
$(x+\sqrt 3)(x-\sqrt 3)=0\implies x^2-3=0$
or, $x^2-3=0$
