Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 608: 39

$x=${$0, \dfrac{8}{3}$}

Given: $(3x-4)^2=16$ Need to apply square root property. $(3x-4)^2=16$ This implies that $3x-4=\pm \sqrt {16}$ or, $3x-4=\pm 4$ or, $x=\dfrac{4 - 4}{3},\dfrac{4 + 4}{3}$ Hence, our solution set is: $x=${$0, \dfrac{8}{3}$}