Answer
{$1 -\sqrt 2,1 +\sqrt 2$}
Work Step by Step
Re-write the given equation as: $x^2-2x-1=0$
Factorize the expression with the help of quadratic formula. Quadratic formula suggests that $x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$
This implies that $x=\dfrac{-(-2) \pm \sqrt{(-2)^2-4(1)(-1)}}{2(1)}$
or, $x=\dfrac{2 \pm 2\sqrt 2}{2}$
or, $x=\dfrac{2 (1\pm \sqrt 2)}{2}$
or, $x=1 -\sqrt 2,1 +\sqrt 2$
Hence, our solution set is: {$1 -\sqrt 2,1 +\sqrt 2$}
