Answer
$x=${$\dfrac{1- \sqrt {15}}{4},\dfrac{1+ \sqrt {15}}{4}$}
Work Step by Step
Given: $(4x-1)^2=15$
Need to apply square root property.
$(4x-1)^2=15$
This implies that $4x-1=\pm \sqrt {15}$
or, $4x=1\pm \sqrt {15}$
or, $x=\dfrac{1- \sqrt {15}}{4},\dfrac{1+ \sqrt {15}}{4}$
Hence, our solution set is:
$x=${$\dfrac{1- \sqrt {15}}{4},\dfrac{1+ \sqrt {15}}{4}$}
