Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 608: 32

{$\dfrac{-1}{2},1$}

Re-write the given equation as: $2x^2-x-1=0$ Factorize the expression as: $2x^2-2x+x-1=0$ This implies that $(2x+1)(x-1)=0$ Need to apply zero-product property. Thus, $x=\dfrac{-1}{2},1$ Hence, our solution set is: {$\dfrac{-1}{2},1$}