Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 608: 52

Answer

$x^2-4x-12=0$

Work Step by Step

As we are given that solution set : {$-2,6$} This implies that $x=-2,6$ As per zero-product reverse property, we have $(x+2)(x-6)=0$ Now, apply FOIL METHOD $(x+2)(x-6)=0 \implies x^2-6x+2x-12=0$ or, $x^2-4x-12=0$
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