Answer
$2\sqrt[3]{x} + 7\sqrt{5}$
Work Step by Step
Regroup the terms to obtain:
$=(3\sqrt[3]{x}-\sqrt[3]{x})+(3\sqrt{5}+4\sqrt{5})$
RECALL:
The distributive property states that for any real numbers a, b, and c:
(1) $ac + bc = (a+b)c$
(2) $ac - bc = (a-b)c$
Use the rules above to combine like terms:
$=(3-1)\sqrt[3]{x} + (3+4)\sqrt{5}
\\=2\sqrt[3]{x} + 7\sqrt{5}$
