Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.4 - Adding, Subtracting, and Dividing Radical Expressions - Exercise Set - Page 538: 16

Answer

$11\sqrt{5x}$

Work Step by Step

Simplify each radical to obtain: $=5\sqrt{9(5x)} - 2\sqrt{4(5x)} \\=5\sqrt{3^2(5x)} - 2\sqrt{2^2(5x)} \\=5(3)\sqrt{5x}- 2(2)\sqrt{5x} \\=15\sqrt{5x} - 4\sqrt{5x}$ RECALL: The distributive property states that for any real numbers a, b, and c: (1) $ac + bc = (a+b)c$ (2) $ac-bc=(a-b)c$ Use rule (2) above to combine like terms and obtain: $=(15-4)\sqrt{5x} \\=11\sqrt{5x}$
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