Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.4 - Adding, Subtracting, and Dividing Radical Expressions - Exercise Set - Page 538: 12

Answer

$3\sqrt{5}$

Work Step by Step

Simplify each radical to obtain: $=\sqrt{5} +\sqrt{4(5)} \\=\sqrt{5} +\sqrt{2^2(5)} \\=\sqrt{5}+2\sqrt{5}$ RECALL: The distributive property states that for any real numbers a, b, and c: (1) $ac + bc = (a+b)c$ (2) $ac-bc=(a-b)c$ Use rule (1) above to combine like terms and obtain: $=(1+2)\sqrt{5} \\=3\sqrt{5}$
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