Answer
$\dfrac{x\sqrt[3]{x^2}}{5y}$
Work Step by Step
RECALL:
The quotient rule:
$\sqrt[n]{\dfrac{a}{b}}=\dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}$
where
$\sqrt[n]{a}$ and $\sqrt[n]{b}$ are real numbers and $b\ne0$
Use the quotient rule above to obtain:
$=\dfrac{\sqrt[3]{x^5}}{\sqrt[3]{125y^{3}}}
\\=\dfrac{\sqrt[3]{x^3(x^2)}}{\sqrt[3]{(5y)^3}}
\\=\dfrac{x\sqrt[3]{x^2}}{5y}$
