Answer
$5x\sqrt[3]{xy^2}$
Work Step by Step
Factor the radicand of the first radical so that one factor is a perfect cube. Then, simplify to obtain:
$=2\sqrt[3]{x^3(xy^2)}+3x\sqrt[3]{xy^2}
\\=2(x)\sqrt[3]{xy^2} + 3x\sqrt[3]{xy^2}
\\=2x\sqrt[3]{xy^2} + 3x\sqrt[3]{xy^2}$
RECALL:
The distributive property states that for any real numbers a, b, and c:
(1) $ac + bc = (a+b)c$
(2) $ac-bc=(a-b)c$
Use the rule (1) above to combine like terms and obtain:
$=(2x+3x)\sqrt[3]{xy^2}
\\=5x\sqrt[3]{xy^2}$
