Answer
$\dfrac{x}{6y^4}$
Work Step by Step
RECALL:
The quotient rule:
$\sqrt[n]{\dfrac{a}{b}}=\dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}$
where
$\sqrt[n]{a}$ and $\sqrt[n]{b}$ are real numbers and $b\ne0$
Use the quotient rule above to obtain:
$=\dfrac{\sqrt{x^2}}{\sqrt{36y^8}}
\\=\dfrac{x}{\sqrt{(6y^4)^2}}
\\=\dfrac{x}{6y^4}$
