Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.4 - Adding, Subtracting, and Dividing Radical Expressions - Exercise Set - Page 538: 10

Answer

$4\sqrt[3]{x} + 8\sqrt{7}$

Work Step by Step

Regroup the terms to obtain: $=(5\sqrt[3]{x}-\sqrt[3]{x})+(6\sqrt{7}+2\sqrt{7})$ RECALL: The distributive property states that for any real numbers a, b, and c: (1) $ac + bc = (a+b)c$ (2) $ac - bc = (a-b)c$ Use the rules above to combine like terms: $=(5-1)\sqrt[3]{x} + (6+2)\sqrt{7} \\=4\sqrt[3]{x} + 8\sqrt{7}$
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