Answer
$6\sqrt{2x}$
Work Step by Step
Simplify each radical to obtain:
$=3\sqrt{16(2x)} - 2\sqrt{9(2x)}
\\=3\sqrt{4^2(2x)} -2\sqrt{3^2(2x)}
\\=3(4)\sqrt{2x}- 2(3)\sqrt{2x}
\\=12\sqrt{2x} - 6\sqrt{2x}$
RECALL:
The distributive property states that for any real numbers a, b, and c:
(1) $ac + bc = (a+b)c$
(2) $ac-bc=(a-b)c$
Use rule (2) above to combine like terms and obtain:
$=(12-6)\sqrt{2x}
\\=6\sqrt{2x}$
