Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - Exercise Set - Page 428: 80

Answer

$ T(x)=\frac{720x+48050}{(x+70)(x+65)}$. $T(5)=10$.

Work Step by Step

The given function is $\Rightarrow T(x)=\frac{470}{x+70}+\frac{250}{x+65}$. The LCD of the denominators is $(x+70)(x+65)$. Multiply the numerators and the denominators $\Rightarrow T(x)=\frac{470(x+65)}{(x+70)(x+65)}+\frac{250(x+70)}{(x+70)(x+65)}$ Add both numerators because denominators are equal. $\Rightarrow T(x)=\frac{470(x+65)+250(x+70)}{(x+70)(x+65)}$ $\Rightarrow T(x)=\frac{470x+30550+250x+17500}{(x+70)(x+65)}$ Add like terms. $\Rightarrow T(x)=\frac{720x+48050}{(x+70)(x+65)}$ Replace $x$ with $5$. $\Rightarrow T(5)=\frac{720(5)+48050}{(5+70)(5+65)}$ Simplify. $\Rightarrow T(5)=\frac{3600+48050}{(75)(70)}$ $\Rightarrow T(5)=\frac{51650}{5250}$ $\Rightarrow T(5)=9.8380952381$ Rounded to the nearest hour: $\Rightarrow T(5)=10$.
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