Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - Exercise Set - Page 428: 71

Answer

$ -\frac{1}{x(x+h)} $.

Work Step by Step

The given expression is $\Rightarrow \left ( \frac{1}{x+h}-\frac{1}{x} \right) \div h$ The LCD of the denominators in the bracket is $x(x+h)$. Multiply the numerator and denominator $\Rightarrow \left ( \frac{x}{x(x+h)}-\frac{x+h}{x(x+h)} \right) \div h$ Add numerators in the bracket because both denominators are equal. $\Rightarrow \left ( \frac{x-(x+h)}{x(x+h)} \right) \div h$ Simplify. $\Rightarrow \left ( \frac{x-x-h}{x(x+h)} \right) \div h$ $\Rightarrow \left ( \frac{-h}{x(x+h)} \right) \div h$ Invert the divisor and multiply. $\Rightarrow \left ( \frac{-h}{x(x+h)} \right) \cdot \frac{1}{h} $ Cancel common terms. $\Rightarrow -\frac{1}{x(x+h)} $.
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