Answer
$\frac{x+2}{x+6}$ and $x\ne3$.
Work Step by Step
$\frac{x^2-x-6}{x^2+3x-18}=\frac{x^2-3x+2x-6}{x^2+6x-3x-18}=\frac{x(x-3)+2(x-3)}{x(x+6)-3(x+6)}=\frac{(x-3)(x+2)}{(x+6)(x-3)}=\frac{x+2}{x+6}$ and $x\ne3$.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Mid-Chapter Check Point - Page 447: 1
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