Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Mid-Chapter Check Point - Page 447: 7

Answer

$x+y$.

Work Step by Step

The given expression is $=\frac{x^3y-y^3x}{x^2y-xy^2}$ Factor out $xy$ from the numerator and denominator. $=\frac{xy(x^2-y^2)}{xy(x-y)}$ Factor $x^2-y^2$. Use the algebraic identity $a^2-b^2=(a+b)(a-b)$. $=(x+y)(x-y)$. Substitute the factor. $=\frac{xy(x+y)(x-y)}{xy(x-y)}$ Cancel common terms. $=x+y$.
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