Answer
$ \frac{7x+4}{4(x+1)}$.
Work Step by Step
The given expression is
$=\frac{\frac{3}{x+1}+\frac{4}{x}}{\frac{4}{x}}$
Multiply the numerator and denominator by $x(x+1)$.
$=\frac{x(x+1)}{x(x+1)}\cdot \frac{\frac{3}{x+1}+\frac{4}{x}}{\frac{4}{x}}$
Use the distributive property.
$= \frac{x(x+1)\cdot\frac{3}{x+1}+x(x+1)\cdot\frac{4}{x}}{x(x+1)\cdot\frac{4}{x}}$
Simplify.
$= \frac{3x+4(x+1)}{4(x+1)}$
$= \frac{3x+4x+4}{4x+4}$
$= \frac{7x+4}{4x+4}$
$= \frac{7x+4}{4(x+1)}$.