Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.4 - Matrix Solutions to Linear Systems - Exercise Set - Page 229: 11

Answer

The answer is $\left[\begin{array}{ccc|c} 1& -3 & 2&0 \\ 0 &10 &-7& 7 \\ 2&-2&1&3\\ \end{array}\right]$.

Work Step by Step

The given matrix is $\left[\begin{array}{ccc|c} 1& -3 & 2&0 \\ 3 &1 &-1&7 \\ 2&-2&1&3\\ \end{array}\right]$ Perform $ -3R_1+R_2 $ Multiply row one by $-3$ and add to the row two as shown below. $\left[\begin{array}{ccc|c} 1& -3 & 2&0 \\ -3\cdot 1+3 &-3\cdot (-3)+ 1 &-3\cdot 2-1&-3\cdot 0+ 7 \\ 2&-2&1&3\\ \end{array}\right]$ Simplify. $\left[\begin{array}{ccc|c} 1& -3 & 2&0 \\ -3+3 &9+ 1 &-6-1& 0+ 7 \\ 2&-2&1&3\\ \end{array}\right]$ $\left[\begin{array}{ccc|c} 1& -3 & 2&0 \\ 0 &10 &-7& 7 \\ 2&-2&1&3\\ \end{array}\right]$.
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