Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.4 - Matrix Solutions to Linear Systems - Exercise Set - Page 229: 10

Answer

The answer is $\left[\begin{array}{ccc|c} 1& -4 & 2&3 \\ 1 &-4 &4&0 \\ 2&0&7&4\\ \end{array}\right]$.

Work Step by Step

The given matrix is $\left[\begin{array}{ccc|c} 3 & -12 & 6&9 \\ 1 &-4 &4&0 \\ 2&0&7&4\\ \end{array}\right]$ Perform $\frac{1}{3}R_1 $ Multiply row one by $ \frac{1}{3} $ $\left[\begin{array}{ccc|c} 3\cdot \frac{1}{3}& -12\cdot \frac{1}{3} & 6\cdot \frac{1}{3}&9\cdot \frac{1}{3} \\ 1 &-4 &4&0 \\ 2&0&7&4\\ \end{array}\right]$ Simplify. $\left[\begin{array}{ccc|c} 1& -4 & 2&3 \\ 1 &-4 &4&0 \\ 2&0&7&4\\ \end{array}\right]$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.