Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review - Page 329: 9

Answer

$-x^{2}y^{7}z$

Work Step by Step

$-xy^{2}\times y^{3}\times xy^{2}z=-(xy^{2}\times y^{3}\times xy^{2}z)=-(x^{1+1}\times y^{2+3+2}\times z)=-x^{2}y^{7}z$
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