Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review - Page 329: 23

Answer

$27x^{3}$

Work Step by Step

$(3x)^{3}=3x\times3x\times3x=(3\times3\times3) \times (x^{1+1+1})=27x^{3}$
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