Answer
$2y^{x-7}$
Work Step by Step
Using laws of exponents, the given expression, $
\dfrac{4y^{3x-3}}{2y^{2x+4}}
$, simplifies to
\begin{array}{l}
2y^{3x-3-(2x+4)}
\\\\
2y^{3x-3-2x-4}
\\\\
2y^{x-7}
.\end{array}
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