Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review - Page 329: 22

Answer

$\frac{a^{2}}{16}$

Work Step by Step

$(\frac{a}{4})^{2}=\frac{a}{4}\times\frac{a}{4}=\frac{a\times a}{4\times4}=\frac{a^{2}}{16}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.