Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review - Page 329: 15

Answer

$\frac{1}{y^{5}}$

Work Step by Step

$\frac{y^{6p-3}}{y^{6p+2}}=y^{6p-3-(6p+2)}=y^{6p-3-6p-2}=y^{-5}=\frac{1}{y^{5}}$
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