Answer
$\frac{9}{16}$
Work Step by Step
$(\frac{4}{3})^{-2}=\frac{1}{(\frac{4}{3})^{2}}=\frac{1}{\frac{4\times4}{3\times3}}=\frac{1}{\frac{16}{9}}=\frac{9}{16}$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Review - Page 329: 27
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