Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review - Page 329: 30

Answer

$\dfrac{-27y^{6}}{x^{6}}$

Work Step by Step

Using laws of exponents, then, \begin{array}{l} \left( -3x^{-2}y^2 \right)^{3} \\\\= (-3)^3x^{-2(3)}y^{2(3)} \\\\= -27x^{-6}y^{6} \\\\= \dfrac{-27y^{6}}{x^{6}} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.