Answer
$\dfrac{-27y^{6}}{x^{6}}$
Work Step by Step
Using laws of exponents, then,
\begin{array}{l}
\left( -3x^{-2}y^2 \right)^{3}
\\\\=
(-3)^3x^{-2(3)}y^{2(3)}
\\\\=
-27x^{-6}y^{6}
\\\\=
\dfrac{-27y^{6}}{x^{6}}
.\end{array}
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