Answer
$\frac{1}{8x^{9}}$
Work Step by Step
$(-2x^{3})^{-3}=(-2)^{-3}\times (x^{3})^{-3}=\frac{1}{(-2)^{3}}\times x^{3\times-3}=\frac{1}{-2\times-2\times-2}\times x^{-9}=\frac{1}{8x^{9}}$
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