Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review - Page 329: 31

Answer

$x^{25}y^{15}z^{15}$

Work Step by Step

Using laws of exponents, then, \begin{array}{l} \left( \dfrac{x^{-5}y^{-3}}{z^3} \right)^{-5} \\\\= \dfrac{x^{-5(-5)}y^{-3(-5)}}{z^{3(-5)}} \\\\= \dfrac{x^{25}y^{15}}{z^{-15}} \\\\= x^{25}y^{15}z^{15} .\end{array}
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