Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review - Page 329: 10

Answer

$12bx^{2}y^{3}$

Work Step by Step

$(-4xy)\times (-3xy^{2}b)=(-4\times -3b)\times x^{1+1}\times y^{1+2}=12bx^{2}y^{3}$
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