Answer
Ellipse
Work Step by Step
$4{{y}^{2}}+20{{x}^{2}}+1=8y-5{{x}^{2}}$
Combine like terms
$4{{y}^{2}}+20{{x}^{2}}+5{{x}^{2}}-8y+1=0$
$25{{x}^{2}}+4{{y}^{2}}-8y+1=0$
Compare the equation $25{{x}^{2}}+4{{y}^{2}}-8y+1=0$ with the standard equation of a conic section
$A{{x}^{2}}+B{{y}^{2}}+Cxy+Dx+Ey+F=0$,
Here,
$A=25,B=4$
Here, we see A and B have the same sign, but $A \ne B$.
Therefore, the graph of the equation is an ellipse.