Answer
Circle
Work Step by Step
$3{{x}^{2}}+{{y}^{2}}-x=2{{x}^{2}}-9x+10y+40$
Combine like terms
$3{{x}^{2}}-2{{x}^{2}}+{{y}^{2}}-x+9x-10y-40=0$
${{x}^{2}}+{{y}^{2}}+8x-10y-40=0$
Compare the equation ${{x}^{2}}+{{y}^{2}}+8x-10y-40=0$ with the standard equation of a conic section $A{{x}^{2}}+B{{y}^{2}}+Cxy+Dx+Ey+F=0$,
Here,
$A=1,B=1$ (A = B)
Therefore, the graph of the equation is a circle.