Answer
None of the lines are parallel since slopes are not equal.
Work Step by Step
For line $a$: $4y+x=8$
$\implies 4y=8-x$
$\implies y=\frac{8-x}{4}=\frac{8}{4}-\frac{x}{4}$
$\implies y=-\frac{1}{4}x+2$
Comparing the above equation with slope-intercept form $y=mx+b$, we find that
the slope of line $a$=$-\frac{1}{4}$
For line $b$: $2y+x=4$
$\implies 2y=-x+4$
$\implies y=-\frac{1}{2}x+\frac{4}{2}$
$\implies y= -\frac{1}{2}x+2$
Comparing the above equation with slope-intercept form $y=mx+b$, we find that
the slope of line $a$=$-\frac{1}{2}$
For line $c$: $2y=-3x+6$
$\implies y=-\frac{3}{2}x+3$
Slope of line $c$= $-\frac{3}{2}$
None of the lines are parallel since slopes are not equal.
