Answer
Line $b$ has a slope of $-\frac{1}{6}$, the negative reciprocal of $6$, so it is perpendicular to line $a$.
Work Step by Step
Line $a:$
$\Rightarrow y=6x-2$.
Slope is $m_a=6$
Line $b:$
$\Rightarrow 6y=-x$.
Slope intercept form is
$\Rightarrow y=-\frac{1}{6}x+0$.
Slope is $m_b=-\frac{1}{6}$
Line $c:$
$\Rightarrow y+6x=1$.
Slope intercept form is
$\Rightarrow y=-6x+1$.
Slope is $m_c=-6$
Line $b$ has a slope of $-\frac{1}{6}$, the negative reciprocal of $6$, so it is perpendicular to line $a$.