Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 4 - Writing Linear Functions - 4.3 - Writing Equations of Parallel and Perpendicular Lines - Exercises - Page 191: 22

Answer

The equation of the perpendicular line is $y=\frac{1}{2}x-3$.

Work Step by Step

The given point is $(8,1)$. The given equation of the line is $\Rightarrow 2y+4x=12$ Slope-intercept form is $\Rightarrow y=-2x+6$ Slope of the line is $m=-2$. Slope of the perpendicular line is $m=\frac{1}{2}$. The slope-intercept form is $\Rightarrow y=mx+b$ Substitute $\frac{1}{2}$ for $m,8$ for $x,$ and $1$ for $y$. $\Rightarrow 1=\frac{1}{2}(8)+b$ Simplify. $\Rightarrow 1=4+b$ Subtract $4$ from each side. $\Rightarrow 1-4=4+b-4$ Simplify. $\Rightarrow -3=b$ The equation of the perpendicular line is $\Rightarrow y=\frac{1}{2}x-3$.
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