Chapter 4 - Writing Linear Functions - 4.3 - Writing Equations of Parallel and Perpendicular Lines - Exercises - Page 191: 12

$y=\frac{3}{2}x-8$

Given: $2y=3x+10$ $y=\frac{3}{2}x+5$ Comparing the above equation with $y=mx+b$, slope $m=\frac{3}{2}$ Slopes are same for parallel lines. So, the slope of required line is $\frac{3}{2}$. Given point is $(2,-5)$ $y-y_{1}=m(x-x_{1})$ $\implies y-(-5)=\frac{3}{2}(x-2)$ $\implies y+5=\frac{3}{2}x-3$ $\implies y=\frac{3}{2}x-3-5$ $\implies y=\frac{3}{2}x-8$