Chapter 4 - Writing Linear Functions - 4.3 - Writing Equations of Parallel and Perpendicular Lines - Exercises - Page 191: 11

$y=\frac{1}{3}x-4$

$3y-x=-12$ $\implies 3y=x-12$ Or $y=\frac{1}{3}x-4$ Comparing the above equation with $y=mx+b$, slope $m=\frac{1}{3}$ Slopes are same for parallel lines. So, the slope of required line is $\frac{1}{3}$. Given point is $(18,2)$ $y-y_{1}=m(x-x_{1})$ $\implies y-2=\frac{1}{3}(x-18)$ $\implies y-2=\frac{1}{3}x-6$ $\implies y=\frac{1}{3}x-6+2$ $\implies y=\frac{1}{3}x-4$