Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.8 Use the Quadratic Formula and the Discriminant - 4.8 Exercises - Skill Practice - Page 296: 48

Answer

$$s=3.25\pm\sqrt3$$

Work Step by Step

We try to get s alone in the equation. Thus, we obtain: $$3=(3.25-s)^2 \\ 3.25-s =\pm \sqrt3 \\ s=3.25\pm\sqrt3$$
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