Answer
$$x=-1\pm .4\sqrt{10}$$
Work Step by Step
We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain:
$$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$
$$x=\frac{10\pm \sqrt{(10)^2-4(5)(-3)}}{2(5)}$$
$$x=-1\pm .4\sqrt{10}$$
