Chapter 4 Quadratic Functions and Factoring - 4.8 Use the Quadratic Formula and the Discriminant - 4.8 Exercises - Skill Practice - Page 296: 19

$$x=-\frac{7}{6}\pm\frac{\sqrt{13}}{6}$$

We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain: $$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$ $$x=\frac{-7\pm \sqrt{(7)^2-4(3)(3)}}{2(3)}$$ $$x=-\frac{7}{6}\pm\frac{\sqrt{13}}{6}$$