Answer
$$x=-1.5\pm .5\sqrt{47}i$$
Work Step by Step
We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain:
$$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$
$$x=\frac{-14\pm \sqrt{(14)^2-4(1)(3)}}{2(1)}$$
$$x=-1.5\pm .5\sqrt{47}i$$