Answer
$$x=\frac{1\pm\sqrt{229}}{12}$$
Work Step by Step
When given the choice to use any method, the quadratic formula is a good choice because it will always work.
We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain:
$$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$
$$x=\frac{2\pm \sqrt{(-2)^2-4(12)(-19)}}{2(12)}$$
$$x=\frac{1\pm\sqrt{229}}{12}$$
