Answer
5, -1
Work Step by Step
We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain:
$$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$
$$x=\frac{4\pm \sqrt{(-4)^2-4(1)(-5)}}{2(-5)}$$
$$x=5,-1$$
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