Chapter 4 Quadratic Functions and Factoring - 4.8 Use the Quadratic Formula and the Discriminant - 4.8 Exercises - Skill Practice - Page 296: 16

$$x=-1\pm\frac{1}{3}\sqrt{39}$$

We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain: $$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$ $$x=\frac{6\pm \sqrt{(6)^2-4(-10)(3)}}{2(3)}$$ $$x=-1\pm\frac{1}{3}\sqrt{39}$$