Answer
$$x=4/3\pm (1/3)\sqrt{43}$$
Work Step by Step
We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain:
$$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$
$$x=\frac{8\pm \sqrt{(-8)^2-4(3)(-9)}}{2(3)}$$
$$x=4/3\pm (1/3)\sqrt{43}$$
