Answer
$$n=\frac{5\pm\sqrt{31}}{3}$$
Work Step by Step
We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain:
$$n=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$
$$n=\frac{10\pm \sqrt{(-10)^2-4(3)(-2)}}{2(3)}$$
$$n=\frac{5\pm\sqrt{31}}{3}$$