Answer
$\frac{1}{2(x+1)}, with$ $x\ne-2$
Work Step by Step
Given : $\frac{\frac{x^{2}-25}{x^{2}+6x+5}}{2x-10}$
This becomes : $\frac{(x-5)(x+5)}{(x+1)(x+5)\times2(x-5)}$
$=\frac{1}{2(x+1)}$
(After dividing out common factors (x-5) and (x+5))